(1/3)^x+2=3^x-1

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Solution for (1/3)^x+2=3^x-1 equation: 



(1/3)^x+2=3^x-1

We move all terms to the left:

(1/3)^x+2-(3^x-1)=0



Domain of the equation: 3)^x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)^x-(3^x-1)+2=0

We get rid of parentheses

(+1/3)^x-3^x+1+2=0

We multiply all the terms by the denominator


(+1-3^x*3)^x+1*3)^x+2*3)^x=0

Wy multiply elements

9x^2+(+1-3^x*3)^x=0

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